ESAT Maths 1 · free worked solution

ESAT Maths 1 probability ratios: use all outcomes

Probability-ratio solution: turn four exhaustive ratio parts into the required 7/10.

Exhaustive probability ratiosSpecification M7.4Reviewed 5 August 2026

Answer first

Option C

The correct answer is

7/107/10

Because the outcomes are exhaustive, every ratio part belongs in the total before you select the requested categories.

This is original UniGenius practice material from the reviewed Maths 1 bank. It is not an official UAT-UK question, past paper, or recalled question.

The question

Read the setup, then choose the shortest valid route

Four mutually exclusive outcomes have probabilities in the ratio 1:2:3:41:2:3:4. What is the probability of an outcome from the last two categories?

  • A1/101/10
  • B1/21/2
  • C7/107/10Answer
  • D3/43/4
  • E9/109/10

Worked solution

The route in 3 steps

  1. The ratio contains 1+2+3+4=101+2+3+4=10 equal parts.

  2. The last two categories contain 3+4=73+4=7 parts.

  3. Their combined probability is 7/107/10.

Next action

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